Josephus problem answer

The subject of the Testimonium Flavianium, the brief passage about Jesus found in the manuscripts of Josephus' Antiquities 18.63-64, came up on this blog not long ago in Larry Behrendt's guest post on Reza Aslan's much-discussed book Zealot: The Life and Times of Jesus of Nazareth from July 24. Behrendt criticizes Aslan for dismissing the Testimonium as a source for information about the ...Answer (1 of 14): The above algorithm is generalised for k skips, there's a nice and fast solution where alternate people are killed. Suppose that n=32 and at the beginning the sword was with person 1. Every time n will reduce to half its size and the sword will return to person 1 and this will...

Josephus and Jesus IV: How Origen gave James a new brother. This is the latest installment of the series on Josephus' Antiquities. We examine the brief mention of a man named James who is described as the "brother of Jesus called Christ.". Those few words, found at 20.9.1.200, are, if authentic, the only known non-Christian mention of ...
But this solution will not handle the case when Josephus(n-1, k)+k becomes n, this will give 0 as the answer. To solve this problem we use the following recursive formula: Josephus(n, k)=(JosephusProblem(n-1, k)+k-1)%n +1. Josephus(n-1, k)+k-1)%n will give an answer between 0 to n-1 and then finally we add 1 to it. BASE CASE:
Everyone, Meet Josephus. Titus Flavius Josephus, usually just called Josephus, lived from 37-100 CE.That makes him too young to be a contemporary of Jesus, of course. All the same, Christians ...
Algorithms - Fourth Edition - Exercise answer 1.3.37. topic. Josephus problem. In this age-old question, N is a desperate man agreed to reduce the number of people living in the following manner. They sat in a circle (position denoted by 0 to N-1) and numbered off from the first person, report M people will be killed, knowing that the last ...
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Answer to We define the Josephus problem as follows. Suppose that n people form a circle and that we are given a positive integer m ≤ n. Beginning with a designated fir | SolutionInn
Josephus problem. A group of n people are standing in a circle, numbered consecutively clockwise from 1 to n. Starting with person no.2, we remove every other person, proceeding clockwise. For example, if n = 6, the people are removed in the order 2, 4, 6, 3, 1, and the last person remaining is no.5. Let j(n) denote the last person remaining.
Answer (1 of 4): I don't know if this is the best method, but it's a relatively good one. Suppose that we start with N legionnaires and every K-th one is killed. In that case, we can frame the problem as follows. We will remove every K-th legionnaire over a first pass around the circle. Then, if...
The problem of Josephus is the following. We are given two positive integers n, q. There are n places arranged around a circle, and numbered clockwise 1, 2, …, n. Each of n people takes one of the places, then (please excuse this, but we didn't invent the problem!) every q th one is executed, until just one remains. More precisely, the occupant of place q is 'removed' first, and in ...
4.14. Simulation: Printing Tasks — Problem Solving with Algorithms and Data Structures. 4.14. Simulation: Printing Tasks ¶. A more interesting simulation allows us to study the behavior of the printing queue described earlier in this section. Recall that as students send printing tasks to the shared printer, the tasks are placed in a queue ...
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known of the three is the Wolf, Goat, and Cabbage problem, whose variations have been found not only in other Euro-pean countries but also in several African cultures (Ascher, 1990). But Petković (2009, p. 2) mentioned that what is now known as the Josephus Problem appeared in Ambrose of Milan's book ca. 370 CE. A version of this puzzle is ...